Write program to check leap year or not.

Posted by admin at July 18, 2021

What Is a Leap Year?

Leap years are years where an extra, or intercalary, day is added to the end of the shortest month, February. The intercalary day, February 29, is commonly referred to as leap day.

Leap years have 366 days instead of the usual 365 days and occur almost every four years.

Why Do We Have Leap Years?

Leap days keep our modern-day Gregorian calendar in alignment with Earth’s revolutions around the Sun. It takes Earth approximately 365.242189 days, or 365 days, 5 hours, 48 minutes, and 45 seconds, to circle once around the Sun. This is called a tropical year, and it starts on the March equinox.

However, the Gregorian calendar has only 365 days in a year. If we didn’t add a leap day on February 29 almost every four years, each calendar year would begin about 6 hours before the Earth completes its revolution around the Sun (see illustration).

As a consequence, our time reckoning would slowly drift apart from the tropical year and get increasingly out of sync with the seasons. With a deviation of approximately 6 hours per year, the seasons would shift by about 24 calendar days within 100 years. Allow this to happen for a while, and Northern Hemisphere dwellers will be celebrating Christmas in the middle of summer in a matter of a few centuries.

Leap days fix that error by giving Earth the additional time it needs to complete a full circle around the Sun.

Pseudocode

The pseudocode of this algorithm sould be like this −

procedure leap_year()
   
   IF year%4 = 0 AND year%100 != 0 OR year%400 = 0
      PRINT year is leap
   ELSE
      PRINT year is not leap
   END IF

end procedure

C Program

include 
 int main() {
    int year;
    printf("Enter a year: ");
    scanf("%d", &year);
 // leap year if perfectly divisible by 400
    if (year % 400 == 0) {
       printf("%d is a leap year.", year);
    }
    // not a leap year if divisible by 100
    // but not divisible by 400
    else if (year % 100 == 0) {
       printf("%d is not a leap year.", year);
    }
    // leap year if not divisible by 100
    // but divisible by 4
    else if (year % 4 == 0) {
       printf("%d is a leap year.", year);
    }
    // all other years are not leap years
    else {
       printf("%d is not a leap year.", year);
    }
 return 0;
 }

Python Program:

Python program to check if year is a leap year or not
 year = 2000
 To get year (integer input) from the user
 year = int(input("Enter a year: "))
 if (year % 4) == 0:
    if (year % 100) == 0:
        if (year % 400) == 0:
            print("{0} is a leap year".format(year))
        else:
            print("{0} is not a leap year".format(year))
    else:
        print("{0} is a leap year".format(year))
 else:
    print("{0} is not a leap year".format(year))

JavaScript Program:

// program to check leap year
 function checkLeapYear(year) {
 //three conditions to find out the leap year if ((0 == year % 4) && (0 != year % 100) || (0 == year % 400)) {     console.log(year + ' is a leap year'); } else {     console.log(year + ' is not a leap year'); }
 }
 // take input
 const year = prompt('Enter a year:');
 checkLeapYear(year);

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